A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the velocity of the tennis racket after the collision.

Answer:
The velocity of the tennis racket after the collision 14.966 m/s.
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of tennis racket = 0.311 kg
m₂ = mass of the ball = 0.057 kg
u₁ = velocity of tennis racket before collision = 30.3 m/s
u₂ = velocity of the ball before collision = -19.2 m/s
v₁ = velocity of tennis racket after collision
v₂ = velocity of the ball after collision
Right (+) , Left (-)
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= ( 30.3 * (0.311 - 0.057) - 19.2 * 2 * 0.057 ) / ( 0.311 + 0.057)
= 14.966 m/s.
So, the velocity of the tennis racket after the collision 14.966 m/s.
The velocity of the tennis racket after the collision is 28.58m/s
According to the law of collision, the momentum before collision is equal to the sum of momentum after the collision.
According to the theorem;
Substitute the given masses and velocities to have:
[tex]0.311(30.3)+0.057(19.2) = (0.311+0.057)v\\9.4233+1.0944=0.368v\\v =\frac{10.5177}{0.368}\\v =28.58m/s[/tex]
Hence the velocity of the tennis racket after the collision is 28.58m/s
learn more on collision here: https://brainly.com/question/7538238