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In triangle ΔABC, ∠C is a right angle and C is the height to AB. Find the angles in ΔCBD and ΔCAD if: m∠A = 65°

m∠CDB =
m∠CBD =
m∠BCD =
m∠CDA =
m∠CAD=
m∠ACD =

Respuesta :

sqdancefan

Answer:

  m∠CDB = 90°

  m∠CBD = 25°

  m∠BCD = 65°

  m∠CDA = 90°

  m∠CAD = 65°

  m∠ACD = 25°

Step-by-step explanation:

All of the triangles are similar:

  ΔADC ~ ΔCDB ~ ΔACB

so corresponding angles will be congruent. Of course, the acute angles in a right triangle are complementary, so ∠B = 90° -65° = 25°. Since CD ⊥ AB, both of the angles at D are right angles, 90°.

In the figure, the angles that look like they're the same size are the same size.

Ver imagen sqdancefan

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