contestada

A 505-N rightward force is use to drag a large box across the floor with a constant velocity of 0.62 m/s. The coefficient of friction between the box and the floor is 0.7. Determine the mass of the box.

Respuesta :

onyebuchinnaji

Answer:

73.62 kg

Explanation:

[tex]F_{NET} = F_{a} + F_{f} [/tex]

[tex]F_{NET} = 0[/tex]

Given;

[tex]F_{a} = 505N[/tex]

[tex]0= 505N + F_{f} [/tex]

[tex]F_{f} = -505 N[/tex]

Also

[tex]F_{f} = -\mu*m*g[/tex]

where m is the mass of the box,

g is acceleration due to gravity = 9.8 m/s²

[tex]\mu[/tex] is coefficient of friction = 0.7

-505 = - (m*0.7*9.8)

-505 = -6.86 m

m = 505/6.86

m = 73.62 kg