Answer:
[tex] E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N[/tex]
Explanation:
For this case we assume that we want to find the electrical field at the point P as we can see on the figure attached.
The electrical field wormula is given by:
[tex] E = \frac{K Q}{d^2}[/tex]
Where r is the distance from the point and the charge. On this case we can use the Pythagoras theorem and we got:
[tex] d^2 = (-0.5m)^2 +(-0.4)^2 = 0.41m^2[/tex]
[tex] d =\sqrt{0.41}= 0.64m[/tex]
And now we can replace into the formula since we know that [tex] Q = 2nC= 2x10^{-9}C [/tex] and [tex] K = 8.99 x10^{9} \frac{Nm^2}{C^2}[/tex], and we got:
[tex] E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N[/tex]
