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Help needed in C++ programming!

On a piano, each key has a frequency, and each subsequent key (black or white) is a known amount higher. Ex: The A key above middle C key has a frequency of 440 Hz. Each subsequent key (black or white) has a frequency of 440 * rn, where n is the number of keys from that A key, and r is 2(1/12). Given an initial frequency, output that frequency and the next 3 higher key frequencies. If the input is 440, the output is: 440 493.883 523.251 554.365.

Note: Include one statement to compute r = 2(1/12) using the pow function, then use r in the formula fn = f0 * rn. (You'll have three statements using that formula, different only in the value for n).

Respuesta :

Answer:

#include <iostream>

#include<conio.h>

using namespace std;

void main()

{

float freqk, freqsk1, freqsk2, freqsk3;

cout<<"Enter the Frequency of a Key = "

cin>>freqk;

freqsk1 = freqk * (1) * (1/6);

freqsk2 = freqk * (2) * (1/6);

freqsk3 = freqk * (3) * (1/6);

cout<<"\nFrequency of Key = "<<freqk<<endl;

cout<<"\nFrequency of Subsequent Key 1 = "<<freqsk1<<endl;

cout<<"\nFrequency of Subsequent Key 2 = "<<freqsk2<<endl;

cout<<"\nFrequency of Subsequent Key 3 = "<<freqsk3<<endl;

getch();

}

Explanation:

There are four variables required to store the frequency value of a key and its subsequent keys. All variable are in float values so that answer should calculated in decimal format. With the help of formula calculate the frequency of all subsequent keys with the help of given frequency of key.

asarwar

Answer:

This program is executed in C++ using dev C++, The explanation of the code is given below. However, the expected result of this program after running is attached

Explanation:

#include <iostream>

#include <cmath>

#include<bits/stdc++.h>

using namespace std;

int main ()

{

double key=5;//it will generate next three keys from A;

double freq=440;//frequency ;

cout<<freq<<"     ";//output the frequency

for(double i=2;i<key;i++)//loop to show next three frequency

{

float value = (1.0/12);// store value of (1/12)

double r=pow(2.0,value);//store value of r=2^(1/12);

 

double n=i;//number of ith iteration (number of next key)

double power=pow(r,n);//calculating r^n;

 

double result= freq* power;//function i.e. fn=f0*rn

cout<<result<<"     ";//displaying result

}

 

 

}

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