The overall net force is 40.6 N [N59.5 °W]
Explanation:
Net force in x direction
F_x = 70 cos 30° - 40 = 20.62 N
Net force in y direction
F_y = 70 sin 30° = 35N
The resultant of two forces is
R = [tex]\sqrt{F _x^2 +F _y^2}[/tex]
= [tex]\sqrt{20.62^2 + 35^2}[/tex]
=40.6 N
The direction of resultant is
θ= tan ^-1 ([tex]\frac{35}{20.62}[/tex]
θ=59.5 ° (N59.5 W)
