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A car accelerates uniformly from rest and
reaches a speed of 34.3 m/s in 10.4 s. The
diameter of a tire is 33.2 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slipping.
Answer in units of rev.

Respuesta :

MathPhys

Answer:

171 rev

Explanation:

Given:

ω₀ = 0 rad/s

ω = 34.3 m/s / (0.332 m / 2) = 207 rad/s

t = 10.4 s

Δθ = ½ (ω + ω₀) t

Δθ = ½ (207 rad/s + 0 rad/s) (10.4 s)

Δθ = 1070 rad

Δθ = 171 rev

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