Answers:
a) How many moles of the substrate is hydrolyzed per second per milligram of enzyme when the substrate concentration is much greater than Km?
Answer:
31.1 µmol PPi s-1 mg -1
b) How many moles of active site are there in 1 mg of enzyme?
Answer:
5.0 x 10-8 mol
c) What is the turnover number of the enzyme?
Answer:
3732 s-1 per mol enzyme but there are 6 active sites per enzyme therefore turnover is 622 s-1 (per active site)
Explanation:
i have attached two pictures that explains the methodology as i can not write formulas here that's why i solved it and created a picture for attachment.