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Point M divides AB so that AM :MB =1:2. If A has coordinates (-1,-3) and B has coordinates (8,9) the coordinates of M are

Respuesta :

Answer:

The coordinates of M are M(2, 1).

Step-by-step explanation:

Let the coordinates of M be M(x, y) that divides the line segment joining the points A(-1, -3) and B(8, 9) in the ratio of 1 : 2.

By section formula, we know that coordinates of a point (x, y) that divides the line segment joining the points (x₁, y₁) and (x₂, y₂) in the ratio of m₁ : m₂ are given by,

[tex]x=\frac{m_{1}x_{2} +m_{2}x_{1}}{m_{1}+m_{2}}[/tex]

[tex]y=\frac{m_{1}y_{2}+m_{2}y_{1}}{m_{1}+m_{2}}[/tex]

Now, (x₁, y₁) = (-1, -3); (x₂, y₂) = (8, 9); m₁ : m₂ = 1 : 2.

Now, we will substitute the values of (x₁, y₁), (x₂, y₂) and m₁ : m₂ in the above mentioned section formula.

The coordinates of M(x, y ) are given by,

[tex]x = \frac{1\times 8+2\times(-1) }{1+2} =\frac{8-2}{3} =2\\y = \frac{1\times9+2\times(-3)}{1+2} =\frac{9-6}{3}  = 1[/tex]

So, the coordinates of M are M(2, 1).