Answer:
840.18
Explanation:
Use the equation: Q = mcΔT
m = mass (5 g)
c = specific heat (4.18)
ΔT = change in temperature (65.3-25.1 = 40.2)
[tex]5*4.18*40.2[/tex] = 840.12
The amount of heat required to raise the temperature of the water has been 6.549 kJ.
The specific heat can be defined as the amount of heat required to raise the temperature of 1 gram of a substance by 1 degree celsius.
Q = mc[tex]\Delta[/tex]T
Q = heat required
m = mass = 5 g
c = speific heat capacity = 4.18 J/g K
[tex]\Delta[/tex]T = change in temperature = 65.3 - 25.1 [tex]\rm ^\circ C[/tex]
[tex]\Delta[/tex]T = 40.2 [tex]\rm ^\circ C[/tex]
[tex]\Delta[/tex]T = 313.35 K
Q = 5 [tex]\times[/tex] 4.18 [tex]\times[/tex] 313.35 K
Q = 6,549.015 J
Q = 6.549 kJ.
The amount of heat required to raise the temperature of the water has been 6.549 kJ.
For more information about the specific heat capacity, refer to the link:
https://brainly.com/question/1747943
