contestada

Asa saves dimes and quarters so that he will have exact change for he bus. He dabs and then dumps the container that he has been using for collecting his coins and finds he has 47 coins that are worth $9.50. How many of each coin does he have?

Respuesta :

absor201

Asa has 15 dimes and 32 quarters.

Step-by-step explanation:

Given,

Total coins = 47

Worth of coins = $9.50 = 9.50*100 = 950 cents

1 dime = 10 cents

1 quarter = 25 cents

Let,

Number of dimes = x

Number of quarters = y

According to given statement;

x+y=47      Eqn 1

10x+25y=950   Eqn 2

Multiplying Eqn 1 by 10

[tex]10(x+y=47)\\10x+10y=470\ \ \ Eqn\ 3[/tex]

Subtracting Eqn 3 from Eqn 2

[tex](10x+25y)-(10x+10y)=950-470\\10x+25y-10x-10y=480\\15y=480[/tex]

Dividing both sides by 15

[tex]\frac{15y}{15}=\frac{480}{15}\\y=32[/tex]

Putting y=32 in Eqn 1

[tex]x+32=47\\x=47-32\\x=15[/tex]

Asa has 15 dimes and 32 quarters.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/2670657
  • brainly.com/question/2821386

#LearnwithBrainly

Otras preguntas