Answer:
Option E.
Step-by-step explanation:
If A and B are two events and P(A)>P(B), then event A is more likely to occur than event B.
It is given that a fair coin is tossed five times. It means
[tex]P(H)=\frac{1}{2}[/tex]
[tex]P(T)=\frac{1}{2}[/tex]
Probability of H T H T T is
[tex]P(H)P(T)P(H)P(T)P(T)=\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{32}[/tex]
Similarly probability of T H H H H and H T H T H is [tex]\frac{1}{32}[/tex].
Since all events have same probability, therefore all of the above sequences are equally likely.
Thus, the correct option is E.
