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10. A chemical reaction was run in 215.5 mL of H2O. During the reaction, the temperature of the H2O changes from 34.4 oC to 57.6 oC. How much heat (in kJ) did the chemical reaction produce? For H2O, Cp= 4.184 J/(g · oC). Assume the mass of the solution is 215.5 g. Enter your answer as a positive decimal number.

Respuesta :

Answer: 20.9 kJ

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed by water= ?

m= mass of water = 215.5 g

c = specific heat capacity = [tex]4.184J/g^0C[/tex]

Initial temperature of the water = [tex]T_i[/tex] = 34.4°C

Final temperature of the water = [tex]T_f[/tex]  = 57.6°C

Change in temperature ,[tex]\Delta T=T_f-T_i=(57.6-34.4)^0C=23.2^0C[/tex]

Putting in the values, we get:

[tex]Q=215.5\times 4.184\times 23.2^0C[/tex]

[tex]Q=20918J=20.9kJ[/tex]    (1kJ=1000J)

The heat absorbed by water is equal to the heat released during the reaction. Thus heat produced by chemical reaction is 20.9 kJ