Answer: [tex]94.24\ in^3[/tex]
Step-by-step explanation:
For this exercise you need to used the formula for calculate the volume of a cone:
[tex]V=\frac{1}{3}\pi r^2h[/tex]
Where "r" is the radius and "h" is the height of the cone.
In this case, you know that the diameter of the cone shaped strainer is:
[tex]d=6\ in[/tex]
Since the radius is half the diameter:
[tex]r=\frac{d}{2}\\\\r=\frac{6\ in}{2}\\\\r=3\ in[/tex]
And the height is:
[tex]h=10\ in[/tex]
Therefore, the final step is to substitute those values into the formula and evaluate, in order to find the amount of cubic inches the cone will hold.
This is:
[tex]V=\frac{1}{3}\pi (3\ in)^2(10\ in)\\\\V=94.24\ in^3[/tex]
