Answer:
length=15.85m . width= 7.85m
Step-by-step explanation:
Given the rectangle pool is 8m longer than its width.
Let the width of the rectangle be x , now the length of the rectangle pool is x+8
Also given there is a walkway of 2m wide in all the directions So the length of the pool and the width increases by 2m
Now length = x+10 and width = x+2
given the area of the rectangle = 176[tex]m^{2}[/tex]
The area of the pool= [tex]length\times width[/tex]
Now [tex](x+10)\times(x+2)=176[/tex]
[tex]x^{2} +12x+20=176[/tex]
[tex]x^{2} +12x-156=0[/tex]
[tex]x=\frac{-12 +\sqrt{12^{2}-4\times 1 \times (-156) } }{2\times 1}[/tex]
on solving we get x=7.85m
Now the length is x+8=15.85m
