The fan cart pushes the air back with a force of 0.24 N
Explanation:
The force applied by the air on the fan cart in order to push it forward can be calculated using Newton's second law:
[tex]F=ma[/tex]
where
F is the force on the fan cart
m is the mass of the cart
a is its acceleration
Here we have
m = 0.3 kg
[tex]a=0.8 m/s^2[/tex]
Therefore, the force exerted by the air on the cart is
[tex]F=(0.3)(0.8)=0.24 N[/tex]
But here we are actually asked to find the force applied by the fan cart on the air. This can be done by using Newton's third law, which states that:
"When an object A exerts a force (action) on an object B, then object B exerts an equal and opposite force (reaction) on object A"
This means that as the air exerts a force (the action) on the fan cart, then the fan cart pushes back the air with an equal and opposite force (the reaction).
So, the cart pushes the air back with a force of 0.24 N as well.
Learn more about Newton's laws here:
Newton’s second law: brainly.com/question/3820012
Newton’s third law: brainly.com/question/11411375
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