a well-designed boiler evaporates 8.5 pounds of water per pound of coal burned. find how many pounds of coal would be necessary to evaporate 68 pounds of water.
Answer: 8 Explanation: 8.5 Per 1 pound can be written as 8.5/1 8.5/1 = 68/? . To find the kissing component you must do 8.5 divided by 68. That should be 8
