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A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of 35 m. If he completes the 200 m dash in 30.0 s and runs at constant speed throughout the race, what is the magnitude of his centripetal acceleration (in m/s2) as he runs the curved portion of the track? m/s2

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Answer

given,

distance = 200 m

radius of curvature = 35 m

time = 30 s

centripetal acceleration = ?

speed of the runner

[tex]v = \dfrac{d}{t}[/tex]

[tex]v = \dfrac{200}{35}[/tex]

v = 5.71 m/s

acceleration of the runner

[tex]a_c = \dfrac{v^2}{r}[/tex]

[tex]a_c = \dfrac{5.71^2}{35}[/tex]

[tex]a_c = 0.931 m/s^2[/tex]

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