Answer:
19 seconds
Explanation:
Heat energy was supplied and used to heat 0.50 liters of water from 0°C to 10°C.
This means water gained heat energy that was supplied.
Therefore;
Heat supplied = Heat gained by water
We are required to calculate the time taken to raise the temperature of water from 0°C to 10°C.
Step 1: Calculate the heat gained by water
Quantity of heat = Mass × specific heat capacity × change in temperature
Density of water 1 g/ml
Volume of water is 500 mL
Therefore, since Mass = density × volume
The mass of water = 500 g
Change in temperature = 10° C
Specific heat capacity of water = 4.18 J/g/°C
Thus;
Quantity of heat = 500 g × 4.18 J/g/°C × 10
= 20,900 Joules
Step 2: Heat supplied by a heater
Heat supplied = Power × time
Power = 1100 J/s
Assuming the time required is x
Heat supplied = 1100x Joules
Step 3: Time required
Remember; heat supplied = heat gained by water
Therefore;
1100x joules = 20,900 Joules
x = 20,900/1100
= 19 seconds
Therefore, the time required to raise the temperature of water from 0°C to 10°C is 19 seconds.
