Respuesta :
Answer: Option (A) is the correct answer.
Explanation:
A neutralization reaction is defined as the reaction in which an acid reacts with a base to yield salt and water.
The given reaction will be as follows.
[tex]HCl + NaOH \rightarrow NaCl + H_{2}O[/tex]
[tex]H_{2}SO_{4} + 2NaOH \rightarrow Na_{2}SO_{4} + 2H_{2}O[/tex]
Now, if molarity of NaOH = [tex]M_{1}[/tex] and volume of NaOH = [tex]V_{1}[/tex]
Therefore, Molarity of HCl = molarity of [tex]H_{2}SO_{4}[/tex] = [tex]M_{2}[/tex]
Volume of HCl required = [tex]\text{molarity of NaOH} \times \frac{\text{volume of NaOH}}{\text{molarity of HCl}}[/tex]
= [tex]\frac{M_{1}V_{1}}{M_{2}}[/tex]
So, vVolume of [tex]H_{2}SO_{4}[/tex] required = 0.5 x molarity of NaOH x \frac{\text{volume of NaOH}}{\text{molarity of H_{2}SO_{4}}}[/tex]
= [tex]0.5 \times \frac{M_{1}V_{1}}{M_{2}}[/tex]
Hence, volume of HCl = 2 x volume of [tex]H_{2}SO_{4}[/tex].
Thus, we can conclude that HCl solution would be required more volume (in mL) to neutralize the base.
