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Two point charges are brought closer together, increasing the force between them by a factor of 17. By what factor was their separation decreased? In other words, if r1 is the original separation and r2 is the final separation, what is the ratio r1/r2?

Respuesta :

Answer:

[tex]\dfrac{r_1}{r_2}=4.123[/tex]

Explanation:

Given:

Final force between them=17(initial force between them)

initial separation between them [tex]r_1[/tex]

Final separation between them [tex]r_2[/tex]

Let Q and q be the charges on them then

[tex]F_2=17F_1\\\dfrac{kQq}{r_2^2}=17\dfrac{kQq}{r_1^2}\\\dfrac{r_1^2}{r_2^2}=17\\\dfrac{r_1}{r_2}=4.123[/tex]

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