[tex]\bf 3x^3+27x^2-15x\div 3x\implies \cfrac{3x^3+27x^2-15x}{3x}\implies \stackrel{\textit{distributing the denominator}}{\cfrac{3x^3}{3x}+\cfrac{27x^2}{3x}-\cfrac{15x}{3x}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^2+9x-5~\hfill[/tex]
63-5x
So you do PEMDAS
There aren’t any parenthesis
There aren’t any exponents
So you multiply 3*3 and get 9
Multiply 27 by 2 and get 54
And divide 15x by 3x
Now moving on to addition/subtraction
The equation is now 9+54-5x
9+54 is 63
So the answer is 63+5x
