contestada

1) A light bulb takes in 30 of energy per second. It transfers 3j as use
energy. Calculate the efficiency.
second. It transfers 3j as useful light energy and 27J as heat energy. Calculate the efficiency

Respuesta :

znk

Answer:

[tex]\boxed{\text{10 \%}}[/tex]

Explanation:

The formula for efficiency is  

[tex]\begin{array}{rcl}\text{Efficiency} & = & \dfrac{\text{useful energy out}}{\text{energy in}} \times 100 \,\% \\\\\eta & = & \dfrac{w_{\text{out}}}{w_{\text{in}} } \times 100 \,\%\\\end{array}[/tex]

Data:

Useful energy =  3 J

Energy input  = 30 J

Calculation:

[tex]\begin{array}{rcl}\eta & = & \dfrac{\text{3 J}}{\text{30 J}} \times 100 \,\%\\\\\eta & = & 10 \, \%\\\end{array}\\\text{ The efficiency is }\boxed{\textbf{10 \%}}[/tex]