Answer:
first question - x^2
second question- A, B, D, and E
Step-by-step explanation:
Correct on EDGE
The solution to the equation is 1±√2
Given the equation (x + 1)^2 – 4(x + 1) + 2 = 0
(x + 1)^2 – 4(x + 1) + 2 = 0
Expand the equation;
x^2+2x+1 - 4x - 4 + 2 = 0
x^2 +2x - 4x - 1 = 0
x^2 - 2x - 1 = 0
Using the general formula;
[tex]x=\frac{-b \pm \sqrt{b^2-4ac} }{2a} \\x=\frac{-(-2) \pm \sqrt{(-2)^2-4(1)(-1)} }{2a} \\x= \frac{2\pm \sqrt{4+4} }{2}\\x=\frac{2\pm\sqrt{8} }{2}\\x=\frac{2\pm2\sqrt{2} }2}\\x= 1 \pm \sqrt{2}[/tex]
Hence the solution to the equation is 1±√2
Learn more here: https://brainly.com/question/18362572
Complete question;
Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution. u = Select the solution(s) of the original equation.
