Factor by grouping
[tex]4r {}^{3} + 10r {}^{2} - 10r - 25[/tex]
A.
[tex](2r {}^{2} + 5)(2r - 5)[/tex]
B.
[tex](2r {}^+ 5)(2r {}^{2} - 5)[/tex]
C.
[tex](2r + 5)(2r {}^{2} - 5)[/tex]
D.
[tex](2r - 5)(2r {}^{2} - 5)[/tex]

Respuesta :

Answer:

C

Step-by-step explanation:

Nice work using latex. I admire anyone who has skills with it.

It looks like this question can be grouped using to sets of brackets.

(4r^3 + 10r^2) : Pull out the common factor. 2r^2* (2r + 5)

The second set of brackets is a little bit tricker. Minus signs are not to be ignored.

(-10r - 25) : -5(2r + 5)

Now put both together,

2r^2(2r + 5) - 5(2r + 5)            

Notice that there is a common factor on either side of that isolated minus sign. The common factor is 2r + 5. Use the distributive property to pull it out.

(2r + 5)(2r^2 - 5)

It looks like C will be the answer.