There are 20 entries in the chess tournament. How many ways can they finish in first, second,
and third place?

Answer:
6840
Step-by-step explanation:
Here, the order matters (1st, 2nd, and 3rd), so we need to use permutations.
There are 20 people who can get in first place. After that, there are 19 people who can get in second place. Finally, there are 18 people who can get in third place. So:
20 * 19 * 18 = 6840
Number of the ways can they finish in first, second, and the third-place is 6840
The linear arrangement of the set of the orders or the linear arrangements of the numbers is called the permutation.
Here, the order matters (1st, 2nd, and 3rd), so we need to use permutations.
There are 20 people who can get in first place. After that, there are 19 people who can get in second place. Finally, there are 18 people who can get in third place. So:
20 x 19 x 18 = 684
Therefore Number of the ways can they finish in first, second, and the third-place is 6840
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