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A container is filled with Neon gas. It has a volume of 1.5L and a pressure of 101.3 kPa. If the volume of the container is increased to 4.00L without removing any of the gas or changing the temperature, what will the new pressure be?Ed Question

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superman1987

Answer:

37.98 kPa.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

  • Knowing that:

P₁ = 101.3 kPa, V₁ = 1.5 L,

P₂ = ??? kPa, V₂ = 4.0 L.

  • Applying in the above equation

(P₁V₁) = (P₂V₂)

∴ P₂ = (P₁V₁)/V₂ = (101.3 kPa)(1.5 L)/(4.0 L) = 37.98 kPa.

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