Answer:
120 mA
Explanation:
The relationship between voltage, current and resistance in a circuit is given by Ohm's law
[tex]I=\frac{V}{R}[/tex]
where
I is the current
V is the voltage
R is the resistance
In this problem, we have an initial current of
I = 60 mA
Then the voltage is doubled:
V' = 2 V
while the resistance is kept the same:
R' = R
So the new current is
[tex]I' = \frac{V'}{R'}=\frac{2V}{R}=2\frac{V}{R}=2 I[/tex]
so, the current has doubled. Since I = 60 mA, the new current is
[tex]I' = 2(60 mA)=120 mA[/tex]
If the voltage impressed across the ends of the circuit were doubled then its new current would be 120 milliAmps
Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
This current-voltage connection may be expressed mathematically as,
The Equation of Ohm's Law is given as;
[tex]\rm V=IR \\\\ I=\frac{V}{R} \\\\[/tex]
If the resistance is constant. The current is directly propotional to the voltage;
If the voltage value is doubled the value of the current in the circuit ios is also doubled. The value of the new current will be;
[tex]\rm I' = 60 \times 2 \\\\ \rm I' = 120 \ mA[/tex]
Hence if the voltage impressed across the ends of the circuit were doubled then its new current would be 120 milliAmps
To learn more the ohm's law refer to the link;
https://brainly.com/question/796939
