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1. What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100
g of the substance increases in temperature from 10 °C to 70°C?
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Respuesta :

superman1987

Answer:

0.4167 J/°C.g.

Explanation:

  • To solve this problem, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by substance (Q = 2500 J).

m is the mass of the substance (m = 100 g).

c is the specific heat of the substance (c = ??? J/°C.g).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 70°C - 10°C = 60°C).

∵ Q = m.c.ΔT

∴ c = Q/(m.ΔT) = (2500 J)/(100 g)(60°C) = 0.4167 J/°C.g.

The study of the chemical and bond is called chemistry. According to the law of thermodynamics, the heat transfer from the high temperature to the low temperature.

The correct answer to the question is 0.4167.

What is specific heat?

  • The specific heat capacity of a substance is the heat capacity of a sample of the substance divided by the mass of the sample. Specific heat is also sometimes referred to as mass heat capacity.

To solve this problem, we can use the relation:

Q = m.c.ΔT,

where,

  • Q is the amount of heat absorbed by a substance (Q = 2500 J).
  • M is the mass of the substance (m = 100 g).
  • C is the specific heat of the substance (c = ??? J/°C.g).
  • ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 70°C - 10°C = 60°C).

Q = m.c.T

After the equation, we can get.

c = [tex]\frac{Q}{(m.T)} = \frac{(2500 J)}{(100 g)(60C)}\\ \\ = 0.4167[/tex]

Hence, the correct answer is 0.4167.

For more information about the heat, refer to the link:-

https://brainly.com/question/4147359

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