For this case we have a factored expression, of a second degree equation:
([tex](x-3) (x + 8) = 0[/tex]
To find the solutions:
we add 3 to both sides of the equation:
[tex]x=3[/tex]
We subtract 8 on both sides of the equation:
[tex]x = -8[/tex]
Thus, the solutions of the equation are:
[tex]x_ {1} = 3\\x_ {2} = - 8[/tex]
Answer:
[tex]x_ {1} = 3\\x_ {2} = - 8[/tex]
