Answer:
[tex]2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}[/tex]
Step-by-step explanation:
It looks like you want to expand the expression ...
[tex]\sqrt{a}\left(2a^2 -\dfrac{4}{a}\right)[/tex]
Use the distributive property and rules of exponents.
[tex]=2a^{(\frac{1}{2}+2)}-4a^{(\frac{1}{2}-1)}\\\\=\boxed{2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}}[/tex]
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The relevant rules of exponents are ...
√a = a^(1/2)
1/a = a^-1
(a^b)(a^c) = a^(b+c)
