Factor the expression below by grouping. 3x-6+xy-2y.
A. (x-2)(3+y)
B.(x+2)(3-y)
C.2(x-2(xy-2y)
D.(3x-6)(Cyrus-2y)

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chelsiewithie chelsiewithie · Answer 1 · 2019-05-16T06:40:59+02:00

A: (x-2)(3+y)

3x - 6 + xy - 2y

(3x - 6) + (xy - 2y)

3(x - 2) + y(x - 2)

Your two terms are: (3 + y) and (x - 2)

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ColinJacobus ColinJacobus · Answer 2 · 2019-06-28T17:24:21+02:00

Answer: The correct option is (A). [tex](x-2)(3+y).[/tex]

Step-by-step explanation: We are given to factor the following expression by grouping :

[tex]E=3x-6+xy-2y~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

Since we are given to factorize the expression (i) by grouping, so we will take 3 common from first two terms and y common from last two terms.

The factorization of expression (i) is as follows :

[tex]E\\\\=3x-6+xy-2y\\\\=3(x-2)+y(x-2)\\\\=(x-2)(3+y).[/tex]

Thus, the required factored form of the given expression is [tex](x-2)(3+y).[/tex]

Option (A) is CORRECT.