A house has 3 rectangular countertops. Each countertop is 4 3/8 by 2 2/5 feet. How many square feet of tile is needed to cover all of the countertops?

Respuesta :

Answer:

[tex]31\frac{1}{2}ft^2[/tex]

Step-by-step explanation:

From the information given each of the three rectangular countertops has dimension [tex]4\frac{3}{8}[/tex] by  [tex]2\frac{2}{5}[/tex] feet.

The area of a rectangular shapes is the product of the dimensions.

Each rectangular countertop has area;

[tex]4\frac{3}{8}\times 2\frac{2}{5}=\frac{35}{8}\times \frac{12}{5} =10\frac{1}{2}ft^2[/tex]

Therefore the number of square feet tiles needed to cover all the countertops is [tex]=3\times 10\frac{1}{2}=31\frac{1}{2}ft^2[/tex]