Answer:
4
Step-by-step explanation:
Remember that to find the distance between any two points on the plane, we should use the distance formula:
[tex]d=\sqrt{(x_2-x_1)+(y_2-y_1)}[/tex]
where
[tex](x_1,y_1)[/tex] are the coordinates of the first point
[tex](x_2,y_2)[/tex] are the coordinates of the second point
We know from our problem that the first point is (-3, 0); therefore, [tex]x_1=-3[/tex] and [tex]y_1=0[/tex]. We also know that the second point is (0, √7), so [tex]x_2=0[/tex] and [tex]y_2=\sqrt{7}[/tex].
Replacing the values:
[tex]d=\sqrt{(x_2-x_1)+(y_2-y_1)}[/tex]
[tex]d=\sqrt{(0-(-3))^2+(\sqrt{7}-2)^2 }[/tex]
[tex]d=\sqrt{(0+3)^2+(\sqrt{7})^2 }[/tex]
[tex]d=\sqrt{(3)^2+7}[/tex]
[tex]d=\sqrt{9+7}[/tex]
[tex]d=\sqrt{16}[/tex]
[tex]d=4[/tex]
We can conclude that the distance between the given points is 4.
