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Let x be the normal distribution with μ=52.1 and σ=7.5. What is the x-value representing the twelfth percentile, P12. (Round to the nearest hundredth.):

Respuesta :

LammettHash

In the standard normal distribution, we have roughly

[tex]P(Z\le-1.1750)\approx0.12[/tex]

so the corresponding [tex]x[/tex] value for the 12th percentile is

[tex]-1.1750\approx\dfrac{x-52.1}{7.5}\implies x\approx43.3[/tex]

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