please help with this if you can.

Answer:
option B
[tex]\frac{x+5}{x-2}[/tex]
Step-by-step explanation:
Given in the question an expression
[tex]\frac{(x-1)(x+5)}{(x-2)(x-1)}[/tex]
The term (x-1) will be cancel out from both, denominator and numerator so we will be left with
[tex]\frac{x+5}{x-2}[/tex]
Answer:
B. [tex]\frac{x+5}{x-2}[/tex]
Step-by-step explanation:
The given rational expression is;
[tex]\frac{(x-1)(x+5)}{(x-2)(x-1)}[/tex]
Where [tex]x\ne2\:or\;1[/tex]
Observe that;
[tex](x-1)[/tex] is common to both the numerator and the denominator.
Cancel it out to obtain;
[tex]\frac{(x+5)}{(x-2)}[/tex]
The correct choice is B.