Answer:
5x10^-3
Explanation:
Hooke's Law states that the force needed to compress or extend a spring is directly proportional to the distance you stretch it.
Hooke's Law can be represented as
where F is the force
k is the spring constant
x is the extension of the material
Plug values in the equation
Step 1 find the original extension
0.045 = (400)x
x = 1.125x 10^-4 m d
Step 2 find the new extension
0.045+2 = 400(x)
2.045 = 400x
x = 5.1125x10^-3
Step 3 subtract the new extension with original
Total extension of the spring = 5.1125x10^-3 - 1.125x 10^-4 m = 5x10^-3
Answer: 0.02m
Explanation:
The other guy is completely wrong. He literally just used the energy store value to fill in the force for the Hooke's Law equation.
Firstly, we calculate the extension using this equation:
Elastic Potential Energy = 0.5 x Spring Constant x (Extension^2)
so 0.045 = 0.5 x 400 x e^2
so e = [tex]\sqrt[]{\frac{0.045}{0.5X400} }[/tex]
so e = 0.015
Now we just need to calculate the extension of 2N, then add it on to 0.015
[tex]\frac{2}{400}[/tex] = 0.005
0.015 + 0.005 = 0.02
The answer is 0.2m
[Also the other guy cannot be correct because his final answer is equal to just the 2N weight, if you can understand what I mean]
Hope this helps. Thanks. Just posted this cuz didn't want people to get the wrong answer.
