Answer: D. 72%
Step-by-step explanation:
The confidence interval for proportion is given by :-
[tex]p\ \pm E[/tex], where E is the margin of error.
Given : Sample size : [tex]n=1000[/tex]
The proportion of the residents of a town : p=0.78
Margin of error : [tex]E=0.08[/tex]
Significance level : [tex]1-0.95=0.05[/tex]
Critical value : [tex]z_{\alpha/2}=1.96[/tex]
Now, the 95% confidence Interval for the proportion of residents of a town will be :-
[tex]0.78\ \pm 0.08=(0.7,\ 0.86)[/tex]
Thus , the
95% confidence Interval for the percentage of residents of a town will be (70%, 86%)
From all the given options only 72 % lies in the confidence interval.
Hence, 72% of the town's residents may favor expanding the park and recreation department
