Respuesta :

kudzordzifrancis

ANSWER

(0,-4)

EXPLANATION

The coordinates of J' are (0,-2).

Let the coordinates of J be (a,b).

Then we apply the rule of the dilation to get,

.

[tex]J( a, b)\to J'( \frac{1}{2} a, \frac{1}{2} b)[/tex]

This implies that,

[tex] \frac{1}{2} a = 0[/tex]

[tex]a = 0[/tex]

And also,

[tex] \frac{1}{2} b = - 2[/tex]

[tex]b = - 4[/tex]

Hence the vertex J of the preimage is

(0,-4)

The first choice is correct.

znk

Answer:

(0, -4)

Step-by-step explanation:

A dilation rule of [tex]D_{O,\frac{1 }{2}}(x,y) \longrightarrow (\frac{1 }{2 }x, \frac{1 }{2 }y)[/tex] means that the coordinates of each point in the pre-image must be divided by 2.

So, we must multiply the coordinates of each point in the image by 2 to get back to the pre-image.

The coordinates of vertex J' are (0, -2), so those of J must have been (0, -4).

Vertex J moved to the origin along the ray until its coordinates were halved.

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