If sec(theta) =25/24, find cot(theta) (Picture provided)

Answer:
B
Step-by-step explanation:
By the definition,
[tex]\sec \theta=\dfrac{\text{hypotenuse}}{\text{adjacent leg}}.[/tex]
If [tex]\sec \theta=\dfrac{25}{24},[/tex] we can consider right triangle with hypotenuse 25 un. and adjacent leg 24 un. By the Pythagorean theorem,
[tex]\text{hypotenuse}^2=\text{adjacent leg}^2+\text{opposite leg}^2,\\ \\\text{opposite leg}^2=25^2-24^2,\\ \\\text{opposite leg}^2=625-576,\\ \\\text{opposite leg}^2=49,\\ \\\text{opposite leg}=7\ un.[/tex]
So,
[tex]\cot \theta=\dfrac{\text{adjacent leg}}{\text{opposite leg}}=\dfrac{24}{7}.[/tex]
Answer:
The correct answer is option b
Cot θ = 24/7
Step-by-step explanation:
Sec θ = Hypotenuse/Adjacent side
Cot θ = Adjacent side/Opposite side
It is given that,
secθ = 25/24
Hypotenuse =25
Adjacent side = 24
To find opposite side
Opposite side of θ = √(25² - 24²) = √625 - 576 = 7
To find cot θ
Cot θ = Adjacent side/Opposite side = 24/7
Therefore the correct answer is option b
Cot θ = 24/7