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A 12.0 V battery is connected into a circuit with two resistors in parallel. One resistor has resistance of 10 Ω and the other has resistance of 32 Ω. What is the total current in the circuit? Show all work and include units of measure.

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jcherry99

Answer:

Explanation:

The current running through the 10 ohm resistor is I = E/R

E = 12 volts

R = 10 ohms

I = 12/10 = 1.2 amperes.

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The current running through the 32 ohm resistor is

E = 12 volts

R = 32 ohms

I = 12 / 32

I = 0.375 amps or 3/8 of an ampere.

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