If (x) = x / x^2-16 what is the value of f(-10)

Answer:
[tex]f(-10)=-\dfrac{5}{42}[/tex]
Step-by-step explanation:
You just replace 'x' for the value given, -10.
[tex]f(x)=\dfrac{x}{x^2-16}\\\\\\f(-10)=\dfrac{-10}{(-10)^2-16}=\dfrac{-10}{100-16}=\dfrac{-10}{84}\\\\\\\\\\f(-10)=-\dfrac{5}{42}[/tex]
The value of the f(-10) is -5/42
We have given that,
[tex]f (x) = x / x^2-16[/tex]
We have to determine the value of the f(-10)
We just replace the value of x by -10 therefore we get,
A function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function. Functions were originally the idealization of how a varying quantity depends on another quantity.
Therefore we get,
[tex]f(-10)=\frac{-10}{(-10)^2-16}[/tex]
[tex]f(-10)=\frac{-10}{100-16} \\f(-10)=-\frac{5}{42}[/tex]
Therefore the value of the f(-10) is -5/42.
To learn more about the function visit:
https://brainly.com/question/4025726
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