The trait of “freckles” is dominant and represented by A. No freckles is recessive and represented by a. A researcher crossed two individuals, one homozygous dominant and the other heterozygous for freckles. Based on the data in the Punnett square, the researcher concluded that all offspring would have dominant as well as the recessive alleles. What comment would you make about his conclusion?

In the Punnett square, we will use F to represent the dominant freckles gene and f to represent the recessive lack-of-freckles gene. The first individual would have FF, because homozygous means that both alleles are the same. The second individual would have Ff, because heterozygous means that it has 2 different alleles. If the first individual passes down one of its "F" alleles and the second individual passes down its "F" allele, the offspring would have 2 dominant alleles, and the researcher's conclusion is disproven.

sarahzulu11 sarahzulu11 · Answer 2 · 2020-03-07T20:07:43+01:00

sarahzulu11 sarahzulu11

07-03-2020

Answer:

the possible solutions are AA, AA, Aa, Aa

The researchers conclusion is incorrect. Although the offspring all have dominant alleles, not all of them will have a recessive allele.

Answer Link