Answer:
Explanation:
1) Data:
a) M = ?
b) mass of solue = 17 g
c) solute: NH₃
d) V = 0.5o liter
2) Formulae:
a) number of moles, n = mass in grams / molar mass
b) M = n / V (in liters)
3) Solution
a) Molar mass of NH₃ = 17.03 g/mol
b) n = mass in grams / molar mass = 17 g / 17.03 g/mol = 0.998 mol NH₃
c) M = n / V (in liters) = 0.998 mol / 0.50 liter = 1.996 M
d) Round to the appropiate number of significant figures, 2: 2.0 M.
Answer: 2.0 M
The molarity of a solution that contains 17 g of NH₃ in 0.50 L of solution is 2 M.
Molarity (M) of any solution is deine as the number of moles of solute (n) present in per liter of solution (V) and it is represented as:
M = n/V
Moles of solute will be calculated as:
n = W/M, where
W = given mass of NH₃ = 17g
M = molar mass of NH₃ = 17g/mol
n = 17/17 = 1 mole
Volume of solution = 0.50 L
Molarity will be calculated as:
M = 1mol / 0.50L = 2 M
Hence resultant molarity is 2M.
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