Answer:
0.129 L = 129.0 mL.
Explanation:
- NaOH neutralizes acetic acid (CH₃COOH) according to the balanced reaction:
NaOH + CH₃COOH → CH₃COONa + H₂O.
- According to the balanced equation: 1.0 mole of NaOH will neutralize 1.0 mole of CH₃COOH.
no. of moles of CH₃COOH = mass/molar mass = (2.0 g)/(60 g/mol) = 0.033 mole.
no. of moles = (0.258 mol/L)(V)
- At neutralization: no. of moles of NaOH = no. of moles of CH₃COOH
∴ (0.258 mol/L)(V) = 0.033 mole
∴ The volume of NaOH = (0.033 mole)/(0.258 mol/L) = 0.129 L = 129.0 mL.
