Respuesta :
Answer:
The wave with 0.03 time period have the greater frequency
Explanation:
Given in the question,
Period T[tex]_{1}[/tex] of one wave = 0.03 seconds
Period T[tex]_{2}[/tex] of another wave = 1/4 seconds
We know that
T = 1 / f
So,
f[tex]_{1}[/tex] = 33.3 hz
f[tex]_{2}[/tex] = 4 hz
The wave with 0.03 time period have the greater frequency.
Answer:
The first wave has a frequency of 33.3 Hz:
f1 = 1⁄T1
f1 = 1⁄0.03
f1 = 33. 3 Hz
The second wave has a frequency of 4 Hz. f2 = 1⁄T2
f2 = 1⁄1⁄4
f2 = 1 ÷ 1⁄4
f2 = 1 × 4⁄1
f2 = 1⁄1 × 4⁄1
f2 = 4 Hz
Therefore, the first wave has a higher frequency.
Explanation: