Answer:
[tex]27,822[/tex]
Step-by-step explanation:
Let
t-----> the time in decade
P----. the population
we know that
[tex]P=23.473(1+0.12)^{t}[/tex]
we have
[tex]t=(2010-1995)/10=15/10=1.5\ decade[/tex]
substitute
[tex]P=23.473(1.12)^{1.5}=27,822[/tex]