The fan adds 4.32 × 10⁵ J ( = 0.12 kWh ) of thermal energy to the air
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Further explanation
Let's recall the Power formula:
[tex]\boxed {P = E \div t }[/tex]
[tex]\boxed {E = P \times t }[/tex]
where :
E = energy ( J )
P = power ( W )
t = time taken ( s )
Let us now tackle the problem!
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Given:
power of fan = P = 120 W = 0.12 kW
time taken = t = 1 hour
Asked:
thermal energy = E = ?
Solution:
We will calculate the thermal energy as follows:
[tex]P = E \div t[/tex]
[tex]E = P \times t[/tex]
[tex]E = 0.12 \times 1[/tex]
[tex]\boxed {E = 0.12 \texttt{ kWh}}[/tex]
[tex]E = 0.12 \times 3.6 \times 10^6 \texttt{ J}[/tex] → 1 kWh = 3.6 × 10⁶ J
[tex]\boxed {E = 4.32 \times 10^5 \texttt{ J}}[/tex]
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Conclusion:
The fan adds 4.32 × 10⁵ J ( = 0.12 kWh ) of thermal energy to the air
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Learn more
- Velocity of Runner : https://brainly.com/question/3813437
- Kinetic Energy : https://brainly.com/question/692781
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Answer details
Grade: High School
Subject: Mathematics
Chapter: Energy
