Self inductance of a solenoid does not depend on magnetic field or current. When deriving the equation you can see that its self inductance is only dependent on geometric factors
The inductance l of a 0.55-m-long air-filled solenoid containing 9000 loops is 0.106 Henry.
Self-inductance is the property of a coil to resist changes in current in itself.
When current changes through a coil, they induce an EMF. EMF is proportional to the rate of change of current through the coil.
Self inductance is given by L = NBA / i
where N is the no of loops, A is the area of loop, i is the current and B is the magnetic field of solenoid B = μ₀ni = μ₀Ni/l
Then, new expression for Self inductance L = μ₀N²A/l
Given a 0.55-m-long air-filled solenoid 2.7 cm= 0.027 in diameter containing 9000 loops.
Substituting the values, we get
L = = μ₀ (9000)² x π(2.7/2)² / 0.55
L = 0.106 Henry.
Thus, inductance l of a 0.55-m-long air-filled solenoid is 0.106 Henry.
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