Respuesta :
Answer:
Step-by-step explanation:
the answer is a because it is thanks i hope you get it right
Answer with explanation:
The two Starting Points used by Eowyn for deriving Distance formula:
[tex]=A(x_{1},y_{1}) \text{and} B(x_{2},y_{2})[/tex]
Then Eowyn has Drawn the point C
→ She Draw a Horizontal Line From Point A, and a vertical line from point B, and then the point where these lines intersect was named the point [tex]C(x_{3},y_{3})[/tex].
→ She Supposed, AC=b, BC=a
and then, AB=c
→Ruler Postulate
[tex]a=|x_{2}-x_{1}|\\\\b=|y_{2}-y_{1}|[/tex]
With the Help of Pythagorean Theorem and Substitution Property
[tex]c^2=a^2+b^2\\\\AB^2=AC^2+BC^2\\\\AB^2=(x_{2}-x_{1})^2+(y_{2}-y_{1})^2\\\\AB=\pm \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]
As, Distance can't be negative
So, [tex]AB= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]
⇒ Here, a and b should be
[tex]a=|y_{2}-y_{1}|,b=|x_{2}-x_{1}|[/tex]
Option C:→→ Eowyn didn't correctly derive the distance formula. She drew in her auxiliary segments correctly, but she didn't define a, b, and c correctly in order to apply them in the Pythagorean Theorem.
